Let’s consider some binary investments. Stocks that look like loaded coins.

  1. $1.00 stock that is 50% to go up or down $1

    Let’s compute some key metrics:

    Let’s price some options while we’re at it.

    The $1 strike (ATM) call is worth $1 if the stock goes up to $2 and its worthless if it drops to zero.

    ATM call = 50% ($1) + 50% (0) = $.50

    ATM put = 50% ($1) + 50% (0) = $.50

    ATM Straddle = c + p = $1.00

    Let’s look at a skewed example next…


  2. $2.00 stock that is 2/3 to go up $1 or 1/3 to go down $2

ATM call = 66.67% ($1) + 33.33% (0) = $.67

ATM put = 66.67% (0) + 33.33% ($2) = $.67

ATM Straddle = c + p = $1.33

<aside> 🪟 Quick observations before moving ahead

Balanced stock

S = $1.00

MAD = 1

MAD/Stock Price = 1

SD = 1

SD/Stock Price = 1

Straddle = $1.00

Skewed stock

S = $2.00

MAD = 1.33

MAD/Stock Price = .67

SD = 1.41

SD/Stock Price = .71

Straddle = $1.33

This is also seen in the straddle approximation. The straddle is directly proportional to S:

![Untitled](<https://prod-files-secure.s3.us-west-2.amazonaws.com/0cf10c00-9599-48d1-b309-4bb16acbc805/e8fe49aa-51b3-4a1b-b32f-c8b8b2823b6c/Untitled.png>)

Here’s a comparison of 9 stocks. They all are priced fairly (ie zero expectancy) but have increasing stock prices and skew (the increasing prices are just a convenience so I could keep the downside risk constant at “lose 100%”):

Untitled

Discussion

We are looking at examples with increasingly more skew. This is negative skew. The downside is always losing 100%.

That downside volatility is being held fixed while the upside return is shrinking but the fair stock price is counterbalanced by an increased probability of experiencing a positive return.

The combined effect of: